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111331202341 is a prime number
BaseRepresentation
bin110011110101111011…
…0110101010100100101
3101122100212022001200111
41213223312311110211
53311001241433331
6123051142013021
711020614414562
oct1475366652445
9348325261614
10111331202341
114324061a137
12196b0717171
13a66323b1b8
145561d07869
152d68decdb1
hex19ebdb5525

111331202341 has 2 divisors, whose sum is σ = 111331202342. Its totient is φ = 111331202340.

The previous prime is 111331202309. The next prime is 111331202377. The reversal of 111331202341 is 143202133111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 92251305441 + 19079896900 = 303729^2 + 138130^2 .

It is an emirp because it is prime and its reverse (143202133111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111331202341 - 25 = 111331202309 is a prime.

It is a super-2 number, since 2×1113312023412 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111331202041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55665601170 + 55665601171.

It is an arithmetic number, because the mean of its divisors is an integer number (55665601171).

Almost surely, 2111331202341 is an apocalyptic number.

It is an amenable number.

111331202341 is a deficient number, since it is larger than the sum of its proper divisors (1).

111331202341 is an equidigital number, since it uses as much as digits as its factorization.

111331202341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 111331202341 its reverse (143202133111), we get a palindrome (254533335452).

The spelling of 111331202341 in words is "one hundred eleven billion, three hundred thirty-one million, two hundred two thousand, three hundred forty-one".