111331222230013 has 4 divisors (see below), whose sum is σ = 111331984808988. Its totient is φ = 111330459651040.

The previous prime is 111331222229959. The next prime is 111331222230023. The reversal of 111331222230013 is 310032222133111.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 51380611072729 + 59950611157284 = 7168027^2 + 7742778^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-111331222230013 is a prime.

It is a super-3 number, since 3×111331222230013³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 111331222230013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (111331222230023) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 381070456 + ... + 381362497.

It is an arithmetic number, because the mean of its divisors is an integer number (27832996202247).

Almost surely, 2^{111331222230013} is an apocalyptic number.

It is an amenable number.

111331222230013 is a deficient number, since it is larger than the sum of its proper divisors (762578975).

111331222230013 is an equidigital number, since it uses as much as digits as its factorization.

111331222230013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 762578974.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 111331222230013 its reverse (310032222133111), we get a palindrome (421363444363124).

The spelling of 111331222230013 in words is "one hundred eleven trillion, three hundred thirty-one billion, two hundred twenty-two million, two hundred thirty thousand, thirteen".