Base | Representation |
---|---|
bin | 10100101111001011… |
… | …00001110110010101 |
3 | 1001201212221201020221 |
4 | 22113211201312111 |
5 | 140300040212211 |
6 | 5040421354341 |
7 | 542614030213 |
oct | 122745416625 |
9 | 31655851227 |
10 | 11133132181 |
11 | 47a33a9a96 |
12 | 21a85689b1 |
13 | 108569b9a2 |
14 | 778847cb3 |
15 | 4525dac71 |
hex | 297961d95 |
11133132181 has 2 divisors, whose sum is σ = 11133132182. Its totient is φ = 11133132180.
The previous prime is 11133132173. The next prime is 11133132217. The reversal of 11133132181 is 18123133111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9614783025 + 1518349156 = 98055^2 + 38966^2 .
It is a cyclic number.
It is not a de Polignac number, because 11133132181 - 23 = 11133132173 is a prime.
It is a super-3 number, since 3×111331321813 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11133132121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5566566090 + 5566566091.
It is an arithmetic number, because the mean of its divisors is an integer number (5566566091).
Almost surely, 211133132181 is an apocalyptic number.
It is an amenable number.
11133132181 is a deficient number, since it is larger than the sum of its proper divisors (1).
11133132181 is an equidigital number, since it uses as much as digits as its factorization.
11133132181 is an evil number, because the sum of its binary digits is even.
The product of its digits is 432, while the sum is 25.
Adding to 11133132181 its reverse (18123133111), we get a palindrome (29256265292).
The spelling of 11133132181 in words is "eleven billion, one hundred thirty-three million, one hundred thirty-two thousand, one hundred eighty-one".
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