11133220031233 has 4 divisors (see below), whose sum is σ = 11133303440688. Its totient is φ = 11133136621780.

The previous prime is 11133220031231. The next prime is 11133220031267. The reversal of 11133220031233 is 33213002233111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11133220031233 - 2¹ = 11133220031231 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11133220031198 and 11133220031207.

It is not an unprimeable number, because it can be changed into a prime (11133220031231) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41504191 + ... + 41771572.

It is an arithmetic number, because the mean of its divisors is an integer number (2783325860172).

Almost surely, 2^{11133220031233} is an apocalyptic number.

It is an amenable number.

11133220031233 is a deficient number, since it is larger than the sum of its proper divisors (83409455).

11133220031233 is an equidigital number, since it uses as much as digits as its factorization.

11133220031233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 83409454.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 11133220031233 its reverse (33213002233111), we get a palindrome (44346222264344).

The spelling of 11133220031233 in words is "eleven trillion, one hundred thirty-three billion, two hundred twenty million, thirty-one thousand, two hundred thirty-three".