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11133241453 = 79140927107
BaseRepresentation
bin10100101111001011…
…11100100001101101
31001201220011021011001
422113211330201231
5140300102211303
65040424000301
7542614663615
oct122745744155
931656137131
1011133241453
1147a34740a4
1221a8600091
131085709649
14778875a45
1545260d31d
hex29797c86d

11133241453 has 4 divisors (see below), whose sum is σ = 11274168640. Its totient is φ = 10992314268.

The previous prime is 11133241421. The next prime is 11133241459. The reversal of 11133241453 is 35414233111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11133241453 - 25 = 11133241421 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11133241459) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 70463475 + ... + 70463632.

It is an arithmetic number, because the mean of its divisors is an integer number (2818542160).

Almost surely, 211133241453 is an apocalyptic number.

It is an amenable number.

11133241453 is a deficient number, since it is larger than the sum of its proper divisors (140927187).

11133241453 is an equidigital number, since it uses as much as digits as its factorization.

11133241453 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 140927186.

The product of its digits is 4320, while the sum is 28.

Adding to 11133241453 its reverse (35414233111), we get a palindrome (46547474564).

The spelling of 11133241453 in words is "eleven billion, one hundred thirty-three million, two hundred forty-one thousand, four hundred fifty-three".

Divisors: 1 79 140927107 11133241453