1113330000113 has 2 divisors, whose sum is σ = 1113330000114. Its totient is φ = 1113330000112.

The previous prime is 1113329999981. The next prime is 1113330000131. The reversal of 1113330000113 is 3110000333111.

Together with next prime (1113330000131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 657343128289 + 455986871824 = 810767^2 + 675268^2 .

It is a cyclic number.

It is not a de Polignac number, because 1113330000113 - 2⁸ = 1113329999857 is a prime.

It is a super-2 number, since 2×1113330000113² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1113330000091 and 1113330000100.

It is not a weakly prime, because it can be changed into another prime (1113330003113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556665000056 + 556665000057.

It is an arithmetic number, because the mean of its divisors is an integer number (556665000057).

Almost surely, 2^{1113330000113} is an apocalyptic number.

It is an amenable number.

1113330000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1113330000113 is an equidigital number, since it uses as much as digits as its factorization.

1113330000113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 1113330000113 its reverse (3110000333111), we get a palindrome (4223330333224).

The spelling of 1113330000113 in words is "one trillion, one hundred thirteen billion, three hundred thirty million, one hundred thirteen", and thus it is an aban number.