Base | Representation |
---|---|
bin | 10000001100110111101… |
… | …001010010011010101011 |
3 | 10221102200220000000002211 |
4 | 100030313221102122223 |
5 | 121220100001144013 |
6 | 2211242355505551 |
7 | 143302233464341 |
oct | 20146751223253 |
9 | 3842626000084 |
10 | 1113330099883 |
11 | 39a1848a9371 |
12 | 15b92bbb82b7 |
13 | 80ca9686341 |
14 | 3bc579dd991 |
15 | 1de60daa23d |
hex | 10337a526ab |
1113330099883 has 2 divisors, whose sum is σ = 1113330099884. Its totient is φ = 1113330099882.
The previous prime is 1113330099809. The next prime is 1113330099899. The reversal of 1113330099883 is 3889900333111.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1113330099883 - 217 = 1113329968811 is a prime.
It is a super-3 number, since 3×11133300998833 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (1113330099083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556665049941 + 556665049942.
It is an arithmetic number, because the mean of its divisors is an integer number (556665049942).
Almost surely, 21113330099883 is an apocalyptic number.
1113330099883 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113330099883 is an equidigital number, since it uses as much as digits as its factorization.
1113330099883 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 419904, while the sum is 49.
The spelling of 1113330099883 in words is "one trillion, one hundred thirteen billion, three hundred thirty million, ninety-nine thousand, eight hundred eighty-three".
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