Base | Representation |
---|---|
bin | 10100101111001100… |
… | …01101111111110101 |
3 | 1001201220021220022102 |
4 | 22113212031333311 |
5 | 140300112004023 |
6 | 5040425311445 |
7 | 542615412344 |
oct | 122746157765 |
9 | 31656256272 |
10 | 11133313013 |
11 | 47a3512939 |
12 | 21a8635585 |
13 | 10857330a4 |
14 | 778893b5b |
15 | 452624628 |
hex | 29798dff5 |
11133313013 has 2 divisors, whose sum is σ = 11133313014. Its totient is φ = 11133313012.
The previous prime is 11133312997. The next prime is 11133313019. The reversal of 11133313013 is 31031333111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10779007684 + 354305329 = 103822^2 + 18823^2 .
It is an emirp because it is prime and its reverse (31031333111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11133313013 - 24 = 11133312997 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11133313019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5566656506 + 5566656507.
It is an arithmetic number, because the mean of its divisors is an integer number (5566656507).
Almost surely, 211133313013 is an apocalyptic number.
It is an amenable number.
11133313013 is a deficient number, since it is larger than the sum of its proper divisors (1).
11133313013 is an equidigital number, since it uses as much as digits as its factorization.
11133313013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 243, while the sum is 20.
Adding to 11133313013 its reverse (31031333111), we get a palindrome (42164646124).
The spelling of 11133313013 in words is "eleven billion, one hundred thirty-three million, three hundred thirteen thousand, thirteen".
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