Base | Representation |
---|---|
bin | 10000001100110111110… |
… | …010100001110010011111 |
3 | 10221102201001120001211011 |
4 | 100030313302201302133 |
5 | 121220101111202033 |
6 | 2211242523440051 |
7 | 143302263203332 |
oct | 20146762416237 |
9 | 3842631501734 |
10 | 1113332522143 |
11 | 39a186203236 |
12 | 15b930986027 |
13 | 80caa023a2a |
14 | 3bc58070619 |
15 | 1de611d7ccd |
hex | 10337ca1c9f |
1113332522143 has 4 divisors (see below), whose sum is σ = 1113681860920. Its totient is φ = 1112983183368.
The previous prime is 1113332522111. The next prime is 1113332522173. The reversal of 1113332522143 is 3412252333111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1113332522143 - 25 = 1113332522111 is a prime.
It is a super-2 number, since 2×11133325221432 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1113332522173) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 174664608 + ... + 174670981.
It is an arithmetic number, because the mean of its divisors is an integer number (278420465230).
Almost surely, 21113332522143 is an apocalyptic number.
1113332522143 is a deficient number, since it is larger than the sum of its proper divisors (349338777).
1113332522143 is an equidigital number, since it uses as much as digits as its factorization.
1113332522143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 349338776.
The product of its digits is 12960, while the sum is 31.
Adding to 1113332522143 its reverse (3412252333111), we get a palindrome (4525584855254).
The spelling of 1113332522143 in words is "one trillion, one hundred thirteen billion, three hundred thirty-two million, five hundred twenty-two thousand, one hundred forty-three".
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