Base | Representation |
---|---|
bin | 110011110110001100… |
… | …1100101011110000101 |
3 | 101122101111102220102001 |
4 | 1213230121211132011 |
5 | 3311011104444303 |
6 | 123052105145301 |
7 | 11021055016636 |
oct | 1475431453605 |
9 | 348344386361 |
10 | 111340312453 |
11 | 43245781757 |
12 | 196b378b231 |
13 | a6650aa9b6 |
14 | 55631d988d |
15 | 2d69aec31d |
hex | 19ec665785 |
111340312453 has 2 divisors, whose sum is σ = 111340312454. Its totient is φ = 111340312452.
The previous prime is 111340312429. The next prime is 111340312471. The reversal of 111340312453 is 354213043111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 67333503169 + 44006809284 = 259487^2 + 209778^2 .
It is an emirp because it is prime and its reverse (354213043111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 111340312453 - 221 = 111338215301 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111340312423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55670156226 + 55670156227.
It is an arithmetic number, because the mean of its divisors is an integer number (55670156227).
Almost surely, 2111340312453 is an apocalyptic number.
It is an amenable number.
111340312453 is a deficient number, since it is larger than the sum of its proper divisors (1).
111340312453 is an equidigital number, since it uses as much as digits as its factorization.
111340312453 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 111340312453 its reverse (354213043111), we get a palindrome (465553355564).
The spelling of 111340312453 in words is "one hundred eleven billion, three hundred forty million, three hundred twelve thousand, four hundred fifty-three".
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