Base | Representation |
---|---|
bin | 10100101111010100… |
… | …00110101000110001 |
3 | 1001201222012122022222 |
4 | 22113222012220301 |
5 | 140300342101231 |
6 | 5040503210425 |
7 | 542630153462 |
oct | 122752065061 |
9 | 31658178288 |
10 | 11134331441 |
11 | 47a4049012 |
12 | 21a8a46a15 |
13 | 10859cb7cc |
14 | 778a7ad69 |
15 | 45277627b |
hex | 297a86a31 |
11134331441 has 16 divisors (see below), whose sum is σ = 12307075200. Its totient is φ = 10019505408.
The previous prime is 11134331437. The next prime is 11134331447. The reversal of 11134331441 is 14413343111.
It is a cyclic number.
It is not a de Polignac number, because 11134331441 - 22 = 11134331437 is a prime.
It is a super-2 number, since 2×111343314412 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11134331441.
It is not an unprimeable number, because it can be changed into a prime (11134331447) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1258130 + ... + 1266948.
It is an arithmetic number, because the mean of its divisors is an integer number (769192200).
Almost surely, 211134331441 is an apocalyptic number.
It is an amenable number.
11134331441 is a deficient number, since it is larger than the sum of its proper divisors (1172743759).
11134331441 is a wasteful number, since it uses less digits than its factorization.
11134331441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12088.
The product of its digits is 1728, while the sum is 26.
Adding to 11134331441 its reverse (14413343111), we get a palindrome (25547674552).
The spelling of 11134331441 in words is "eleven billion, one hundred thirty-four million, three hundred thirty-one thousand, four hundred forty-one".
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