Base | Representation |
---|---|
bin | 10000001100111101110… |
… | …101101011110110101111 |
3 | 10221102222010112100020121 |
4 | 100030331311223312233 |
5 | 121220303101404403 |
6 | 2211300551025411 |
7 | 143304634645336 |
oct | 20147565536657 |
9 | 3842863470217 |
10 | 1113434013103 |
11 | 39a228522965 |
12 | 15b95a96b267 |
13 | 80cc506a059 |
14 | 3bc6772cd1d |
15 | 1de6a0843bd |
hex | 1033dd6bdaf |
1113434013103 has 2 divisors, whose sum is σ = 1113434013104. Its totient is φ = 1113434013102.
The previous prime is 1113434013067. The next prime is 1113434013113. The reversal of 1113434013103 is 3013104343111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1113434013103 - 213 = 1113434004911 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1113434013113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556717006551 + 556717006552.
It is an arithmetic number, because the mean of its divisors is an integer number (556717006552).
Almost surely, 21113434013103 is an apocalyptic number.
1113434013103 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113434013103 is an equidigital number, since it uses as much as digits as its factorization.
1113434013103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 1113434013103 its reverse (3013104343111), we get a palindrome (4126538356214).
The spelling of 1113434013103 in words is "one trillion, one hundred thirteen billion, four hundred thirty-four million, thirteen thousand, one hundred three".
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