Base | Representation |
---|---|
bin | 10100101111010100… |
… | …01001010100100001 |
3 | 1001201222020012102002 |
4 | 22113222021110201 |
5 | 140300342424213 |
6 | 5040503333345 |
7 | 542630230514 |
oct | 122752112441 |
9 | 31658205362 |
10 | 11134342433 |
11 | 47a40562a5 |
12 | 21a8a51255 |
13 | 1085a03806 |
14 | 778a80d7b |
15 | 452779658 |
hex | 297a89521 |
11134342433 has 4 divisors (see below), whose sum is σ = 11134660608. Its totient is φ = 11134024260.
The previous prime is 11134342411. The next prime is 11134342459. The reversal of 11134342433 is 33424343111.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11134342433 - 216 = 11134276897 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11134342396 and 11134342405.
It is not an unprimeable number, because it can be changed into a prime (11134342463) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 99041 + ... + 179102.
It is an arithmetic number, because the mean of its divisors is an integer number (2783665152).
Almost surely, 211134342433 is an apocalyptic number.
It is an amenable number.
11134342433 is a deficient number, since it is larger than the sum of its proper divisors (318175).
11134342433 is an equidigital number, since it uses as much as digits as its factorization.
11134342433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 318174.
The product of its digits is 10368, while the sum is 29.
Adding to 11134342433 its reverse (33424343111), we get a palindrome (44558685544).
The spelling of 11134342433 in words is "eleven billion, one hundred thirty-four million, three hundred forty-two thousand, four hundred thirty-three".
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