Base | Representation |
---|---|
bin | 10100101111010100… |
… | …01011011101111111 |
3 | 1001201222020122110221 |
4 | 22113222023131333 |
5 | 140300343214411 |
6 | 5040503442211 |
7 | 542630265253 |
oct | 122752133577 |
9 | 31658218427 |
10 | 11134351231 |
11 | 47a4061973 |
12 | 21a8a56367 |
13 | 1085a07813 |
14 | 778a84263 |
15 | 45277c071 |
hex | 297a8b77f |
11134351231 has 4 divisors (see below), whose sum is σ = 11134656792. Its totient is φ = 11134045672.
The previous prime is 11134351219. The next prime is 11134351259. The reversal of 11134351231 is 13215343111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11134351231 - 221 = 11132254079 is a prime.
It is a super-2 number, since 2×111343512312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11134351196 and 11134351205.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11134351211) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 89341 + ... + 173926.
It is an arithmetic number, because the mean of its divisors is an integer number (2783664198).
Almost surely, 211134351231 is an apocalyptic number.
11134351231 is a deficient number, since it is larger than the sum of its proper divisors (305561).
11134351231 is an equidigital number, since it uses as much as digits as its factorization.
11134351231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 305560.
The product of its digits is 1080, while the sum is 25.
Adding to 11134351231 its reverse (13215343111), we get a palindrome (24349694342).
The spelling of 11134351231 in words is "eleven billion, one hundred thirty-four million, three hundred fifty-one thousand, two hundred thirty-one".
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