1113440101 has 4 divisors (see below), whose sum is σ = 1113514272. Its totient is φ = 1113365932.

The previous prime is 1113440099. The next prime is 1113440117. The reversal of 1113440101 is 1010443111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 1010443111 = 43 ⋅23498677.

It is a cyclic number.

It is not a de Polignac number, because 1113440101 - 2¹ = 1113440099 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1113440161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5731 + ... + 47536.

It is an arithmetic number, because the mean of its divisors is an integer number (278378568).

Almost surely, 2^1113440101 is an apocalyptic number.

It is an amenable number.

1113440101 is a deficient number, since it is larger than the sum of its proper divisors (74171).

1113440101 is an equidigital number, since it uses as much as digits as its factorization.

1113440101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 74170.

The product of its (nonzero) digits is 48, while the sum is 16.

The square root of 1113440101 is about 33368.2498941734. The cubic root of 1113440101 is about 1036.4673349212.

Adding to 1113440101 its reverse (1010443111), we get a palindrome (2123883212).

The spelling of 1113440101 in words is "one billion, one hundred thirteen million, four hundred forty thousand, one hundred one".