Base | Representation |
---|---|
bin | 10000001100111110011… |
… | …000011110101010110011 |
3 | 10221102222202200201221110 |
4 | 100030332120132222303 |
5 | 121220312420243011 |
6 | 2211301514324403 |
7 | 143305105324266 |
oct | 20147630365263 |
9 | 3842882621843 |
10 | 1113443134131 |
11 | 39a2326926a9 |
12 | 15b961a29703 |
13 | 80cc6c11803 |
14 | 3bc68a24cdd |
15 | 1de6ac86ba6 |
hex | 1033e61eab3 |
1113443134131 has 4 divisors (see below), whose sum is σ = 1484590845512. Its totient is φ = 742295422752.
The previous prime is 1113443134061. The next prime is 1113443134247. The reversal of 1113443134131 is 1314313443111.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 1113443134131 - 27 = 1113443134003 is a prime.
It is a super-2 number, since 2×11134431341312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1113443134631) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 185573855686 + ... + 185573855691.
It is an arithmetic number, because the mean of its divisors is an integer number (371147711378).
Almost surely, 21113443134131 is an apocalyptic number.
1113443134131 is a deficient number, since it is larger than the sum of its proper divisors (371147711381).
1113443134131 is an equidigital number, since it uses as much as digits as its factorization.
1113443134131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 371147711380.
The product of its digits is 5184, while the sum is 30.
Adding to 1113443134131 its reverse (1314313443111), we get a palindrome (2427756577242).
The spelling of 1113443134131 in words is "one trillion, one hundred thirteen billion, four hundred forty-three million, one hundred thirty-four thousand, one hundred thirty-one".
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