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11134433 = 71156823
BaseRepresentation
bin101010011110…
…010111100001
3202221200120102
4222132113201
510322300213
61034352145
7163432622
oct52362741
922850512
1011134433
116315512
12388b655
1323cb02b
14169ba49
15e9e158
hexa9e5e1

11134433 has 4 divisors (see below), whose sum is σ = 11291328. Its totient is φ = 10977540.

The previous prime is 11134429. The next prime is 11134469. The reversal of 11134433 is 33443111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11134433 - 22 = 11134429 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (11134483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 78341 + ... + 78482.

It is an arithmetic number, because the mean of its divisors is an integer number (2822832).

Almost surely, 211134433 is an apocalyptic number.

It is an amenable number.

11134433 is a deficient number, since it is larger than the sum of its proper divisors (156895).

11134433 is an equidigital number, since it uses as much as digits as its factorization.

11134433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 156894.

The product of its digits is 432, while the sum is 20.

The square root of 11134433 is about 3336.8297828927. The cubic root of 11134433 is about 223.3003319966.

Adding to 11134433 its reverse (33443111), we get a palindrome (44577544).

The spelling of 11134433 in words is "eleven million, one hundred thirty-four thousand, four hundred thirty-three".

Divisors: 1 71 156823 11134433