Base | Representation |
---|---|
bin | 1010001000000111011100… |
… | …0110100010100000100111 |
3 | 1110102110020011200100022112 |
4 | 2202001313012202200213 |
5 | 2424412031134343101 |
6 | 35403050534351235 |
7 | 2226305420411030 |
oct | 242016706424047 |
9 | 43373204610275 |
10 | 11134553434151 |
11 | 3603157155564 |
12 | 12b9b4b4bb51b |
13 | 629ca3790904 |
14 | 2a6cb5699a87 |
15 | 14497e1636bb |
hex | a20771a2827 |
11134553434151 has 8 divisors (see below), whose sum is σ = 13164004060320. Its totient is φ = 9214802841888.
The previous prime is 11134553434139. The next prime is 11134553434159. The reversal of 11134553434151 is 15143435543111.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11134553434151 - 26 = 11134553434087 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11134553434099 and 11134553434108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11134553434159) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 27425008256 + ... + 27425008661.
It is an arithmetic number, because the mean of its divisors is an integer number (1645500507540).
Almost surely, 211134553434151 is an apocalyptic number.
11134553434151 is a deficient number, since it is larger than the sum of its proper divisors (2029450626169).
11134553434151 is an equidigital number, since it uses as much as digits as its factorization.
11134553434151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54850016953.
The product of its digits is 216000, while the sum is 41.
Adding to 11134553434151 its reverse (15143435543111), we get a palindrome (26277988977262).
The spelling of 11134553434151 in words is "eleven trillion, one hundred thirty-four billion, five hundred fifty-three million, four hundred thirty-four thousand, one hundred fifty-one".
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