Base | Representation |
---|---|
bin | 1010001000001001000111… |
… | …0000000011011000110101 |
3 | 1110102111101022221212202110 |
4 | 2202002101300003120311 |
5 | 2424413440113234331 |
6 | 35403203145201233 |
7 | 2226322456541001 |
oct | 242022160033065 |
9 | 43374338855673 |
10 | 11135000524341 |
11 | 3603366563a91 |
12 | 12ba055190219 |
13 | 62a0452ac015 |
14 | 2a6d18bdb701 |
15 | 1449a8529946 |
hex | a2091c03635 |
11135000524341 has 16 divisors (see below), whose sum is σ = 14966888228864. Its totient is φ = 7363249173504.
The previous prime is 11135000524301. The next prime is 11135000524343. The reversal of 11135000524341 is 14342500053111.
It is not a de Polignac number, because 11135000524341 - 223 = 11134992135733 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11135000524299 and 11135000524308.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11135000524343) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1518496 + ... + 4957401.
It is an arithmetic number, because the mean of its divisors is an integer number (935430514304).
Almost surely, 211135000524341 is an apocalyptic number.
It is an amenable number.
11135000524341 is a deficient number, since it is larger than the sum of its proper divisors (3831887704523).
11135000524341 is a wasteful number, since it uses less digits than its factorization.
11135000524341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6480540.
The product of its (nonzero) digits is 7200, while the sum is 30.
Adding to 11135000524341 its reverse (14342500053111), we get a palindrome (25477500577452).
The spelling of 11135000524341 in words is "eleven trillion, one hundred thirty-five billion, five hundred twenty-four thousand, three hundred forty-one".
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