11135402147 has 2 divisors, whose sum is σ = 11135402148. Its totient is φ = 11135402146.

The previous prime is 11135402123. The next prime is 11135402149. The reversal of 11135402147 is 74120453111.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11135402147 - 2⁸ = 11135401891 is a prime.

Together with 11135402149, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11135402149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5567701073 + 5567701074.

It is an arithmetic number, because the mean of its divisors is an integer number (5567701074).

Almost surely, 2^11135402147 is an apocalyptic number.

11135402147 is a deficient number, since it is larger than the sum of its proper divisors (1).

11135402147 is an equidigital number, since it uses as much as digits as its factorization.

11135402147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3360, while the sum is 29.

Adding to 11135402147 its reverse (74120453111), we get a palindrome (85255855258).

The spelling of 11135402147 in words is "eleven billion, one hundred thirty-five million, four hundred two thousand, one hundred forty-seven".