Base | Representation |
---|---|
bin | 10100101111011100… |
… | …10110110000001111 |
3 | 1001202001022021021002 |
4 | 22113232112300033 |
5 | 140301133233111 |
6 | 5040543130515 |
7 | 542642505143 |
oct | 122756266017 |
9 | 31661267232 |
10 | 11135446031 |
11 | 47a473a466 |
12 | 21a92a3a3b |
13 | 1085ccbc28 |
14 | 778c8b223 |
15 | 4528e663b |
hex | 297b96c0f |
11135446031 has 2 divisors, whose sum is σ = 11135446032. Its totient is φ = 11135446030.
The previous prime is 11135446009. The next prime is 11135446039. The reversal of 11135446031 is 13064453111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11135446031 - 26 = 11135445967 is a prime.
It is a super-2 number, since 2×111354460312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11135445985 and 11135446003.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11135446039) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5567723015 + 5567723016.
It is an arithmetic number, because the mean of its divisors is an integer number (5567723016).
Almost surely, 211135446031 is an apocalyptic number.
11135446031 is a deficient number, since it is larger than the sum of its proper divisors (1).
11135446031 is an equidigital number, since it uses as much as digits as its factorization.
11135446031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320, while the sum is 29.
Adding to 11135446031 its reverse (13064453111), we get a palindrome (24199899142).
The spelling of 11135446031 in words is "eleven billion, one hundred thirty-five million, four hundred forty-six thousand, thirty-one".
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