Base | Representation |
---|---|
bin | 10100101111011110… |
… | …10000101000110001 |
3 | 1001202001202022111012 |
4 | 22113233100220301 |
5 | 140301213324441 |
6 | 5040552200305 |
7 | 542644513313 |
oct | 122757205061 |
9 | 31661668435 |
10 | 11135683121 |
11 | 47a4891602 |
12 | 21a9399095 |
13 | 1086082b14 |
14 | 778d0d7b3 |
15 | 4529419eb |
hex | 297bd0a31 |
11135683121 has 2 divisors, whose sum is σ = 11135683122. Its totient is φ = 11135683120.
The previous prime is 11135683099. The next prime is 11135683147. The reversal of 11135683121 is 12138653111.
11135683121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11041806400 + 93876721 = 105080^2 + 9689^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11135683121 is a prime.
It is not a weakly prime, because it can be changed into another prime (11135683421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5567841560 + 5567841561.
It is an arithmetic number, because the mean of its divisors is an integer number (5567841561).
Almost surely, 211135683121 is an apocalyptic number.
It is an amenable number.
11135683121 is a deficient number, since it is larger than the sum of its proper divisors (1).
11135683121 is an equidigital number, since it uses as much as digits as its factorization.
11135683121 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 4320, while the sum is 32.
The spelling of 11135683121 in words is "eleven billion, one hundred thirty-five million, six hundred eighty-three thousand, one hundred twenty-one".
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