Base | Representation |
---|---|
bin | 10100101111011111… |
… | …11001011111000001 |
3 | 1001202002001210222221 |
4 | 22113233321133001 |
5 | 140301234203213 |
6 | 5040555531041 |
7 | 542646111151 |
oct | 122757713701 |
9 | 31662053887 |
10 | 11135850433 |
11 | 47a4996284 |
12 | 21a9459a81 |
13 | 1086111016 |
14 | 778d54761 |
15 | 45297638d |
hex | 297bf97c1 |
11135850433 has 2 divisors, whose sum is σ = 11135850434. Its totient is φ = 11135850432.
The previous prime is 11135850431. The next prime is 11135850443. The reversal of 11135850433 is 33405853111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10170319104 + 965531329 = 100848^2 + 31073^2 .
It is a cyclic number.
It is not a de Polignac number, because 11135850433 - 21 = 11135850431 is a prime.
It is a super-2 number, since 2×111358504332 (a number of 21 digits) contains 22 as substring.
Together with 11135850431, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (11135850431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5567925216 + 5567925217.
It is an arithmetic number, because the mean of its divisors is an integer number (5567925217).
Almost surely, 211135850433 is an apocalyptic number.
It is an amenable number.
11135850433 is a deficient number, since it is larger than the sum of its proper divisors (1).
11135850433 is an equidigital number, since it uses as much as digits as its factorization.
11135850433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21600, while the sum is 34.
The spelling of 11135850433 in words is "eleven billion, one hundred thirty-five million, eight hundred fifty thousand, four hundred thirty-three".
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