Base | Representation |
---|---|
bin | 1010001000001111110001… |
… | …0111101111100110000111 |
3 | 1110102122222222212210202121 |
4 | 2202003330113233212013 |
5 | 2424431121031021202 |
6 | 35404100445150411 |
7 | 2226415010154664 |
oct | 242037427574607 |
9 | 43378888783677 |
10 | 11136789313927 |
11 | 36040a4261092 |
12 | 12ba47425b407 |
13 | 62a26ba755b4 |
14 | 2a70485d6a6b |
15 | 144a605bb537 |
hex | a20fc5ef987 |
11136789313927 has 2 divisors, whose sum is σ = 11136789313928. Its totient is φ = 11136789313926.
The previous prime is 11136789313907. The next prime is 11136789313961. The reversal of 11136789313927 is 72931398763111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11136789313927 - 215 = 11136789281159 is a prime.
It is a super-2 number, since 2×111367893139272 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11136789313907) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5568394656963 + 5568394656964.
It is an arithmetic number, because the mean of its divisors is an integer number (5568394656964).
Almost surely, 211136789313927 is an apocalyptic number.
11136789313927 is a deficient number, since it is larger than the sum of its proper divisors (1).
11136789313927 is an equidigital number, since it uses as much as digits as its factorization.
11136789313927 is an evil number, because the sum of its binary digits is even.
The product of its digits is 10287648, while the sum is 61.
The spelling of 11136789313927 in words is "eleven trillion, one hundred thirty-six billion, seven hundred eighty-nine million, three hundred thirteen thousand, nine hundred twenty-seven".
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