Base | Representation |
---|---|
bin | 10000001101011111110… |
… | …000010110011100110101 |
3 | 10221111102210020220110211 |
4 | 100031133300112130311 |
5 | 121222434234240203 |
6 | 2211433235145421 |
7 | 143325014414131 |
oct | 20153760263465 |
9 | 3844383226424 |
10 | 1114003040053 |
11 | 39a49a746272 |
12 | 15ba99445271 |
13 | 81085c0caa7 |
14 | 3bcbd1323c1 |
15 | 1de9eed4c6d |
hex | 1035fc16735 |
1114003040053 has 4 divisors (see below), whose sum is σ = 1114777192320. Its totient is φ = 1113228887788.
The previous prime is 1114003040039. The next prime is 1114003040113. The reversal of 1114003040053 is 3500403004111.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1114003040053 - 25 = 1114003040021 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1114003040023) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 387073975 + ... + 387076852.
It is an arithmetic number, because the mean of its divisors is an integer number (278694298080).
Almost surely, 21114003040053 is an apocalyptic number.
It is an amenable number.
1114003040053 is a deficient number, since it is larger than the sum of its proper divisors (774152267).
1114003040053 is an equidigital number, since it uses as much as digits as its factorization.
1114003040053 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 774152266.
The product of its (nonzero) digits is 720, while the sum is 22.
Adding to 1114003040053 its reverse (3500403004111), we get a palindrome (4614406044164).
The spelling of 1114003040053 in words is "one trillion, one hundred fourteen billion, three million, forty thousand, fifty-three".
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