111403210412131 has 16 divisors (see below), whose sum is σ = 128680066434528. Its totient is φ = 95317942067200.

The previous prime is 111403210412113. The next prime is 111403210412171. The reversal of 111403210412131 is 131214012304111.

It is a cyclic number.

It is not a de Polignac number, because 111403210412131 - 2⁵ = 111403210412099 is a prime.

It is a super-2 number, since 2×111403210412131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 111403210412096 and 111403210412105.

It is not an unprimeable number, because it can be changed into a prime (111403210412171) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 69828591 + ... + 71406151.

It is an arithmetic number, because the mean of its divisors is an integer number (8042504152158).

Almost surely, 2^{111403210412131} is an apocalyptic number.

111403210412131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

111403210412131 is a deficient number, since it is larger than the sum of its proper divisors (17276856022397).

111403210412131 is a wasteful number, since it uses less digits than its factorization.

111403210412131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1955222.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 111403210412131 its reverse (131214012304111), we get a palindrome (242617222716242).

The spelling of 111403210412131 in words is "one hundred eleven trillion, four hundred three billion, two hundred ten million, four hundred twelve thousand, one hundred thirty-one".