11140451201389 has 2 divisors, whose sum is σ = 11140451201390. Its totient is φ = 11140451201388.

The previous prime is 11140451201291. The next prime is 11140451201441. The reversal of 11140451201389 is 98310215404111.

11140451201389 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8594671398889 + 2545779802500 = 2931667^2 + 1595550^2 .

It is an emirp because it is prime and its reverse (98310215404111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11140451201389 - 2¹⁵ = 11140451168621 is a prime.

It is a super-3 number, since 3×11140451201389³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11110451201389) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5570225600694 + 5570225600695.

It is an arithmetic number, because the mean of its divisors is an integer number (5570225600695).

Almost surely, 2^{11140451201389} is an apocalyptic number.

It is an amenable number.

11140451201389 is a deficient number, since it is larger than the sum of its proper divisors (1).

11140451201389 is an equidigital number, since it uses as much as digits as its factorization.

11140451201389 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 34560, while the sum is 40.

The spelling of 11140451201389 in words is "eleven trillion, one hundred forty billion, four hundred fifty-one million, two hundred one thousand, three hundred eighty-nine".