11140591333 has 2 divisors, whose sum is σ = 11140591334. Its totient is φ = 11140591332.

The previous prime is 11140591313. The next prime is 11140591409. The reversal of 11140591333 is 33319504111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8062782849 + 3077808484 = 89793^2 + 55478^2 .

It is an emirp because it is prime and its reverse (33319504111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11140591333 - 2¹³ = 11140583141 is a prime.

It is a super-2 number, since 2×11140591333² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11140591295 and 11140591304.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11140591313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5570295666 + 5570295667.

It is an arithmetic number, because the mean of its divisors is an integer number (5570295667).

Almost surely, 2^11140591333 is an apocalyptic number.

It is an amenable number.

11140591333 is a deficient number, since it is larger than the sum of its proper divisors (1).

11140591333 is an equidigital number, since it uses as much as digits as its factorization.

11140591333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4860, while the sum is 31.

The spelling of 11140591333 in words is "eleven billion, one hundred forty million, five hundred ninety-one thousand, three hundred thirty-three".