Base | Representation |
---|---|
bin | 10100110000000100… |
… | …01110011000000101 |
3 | 1001202102002220001221 |
4 | 22120002032120011 |
5 | 140304001421342 |
6 | 5041250520341 |
7 | 543035000362 |
oct | 123002163005 |
9 | 31672086057 |
10 | 11140654597 |
11 | 47a7677766 |
12 | 21aab960b1 |
13 | 1087103917 |
14 | 779845469 |
15 | 4530c4a67 |
hex | 29808e605 |
11140654597 has 2 divisors, whose sum is σ = 11140654598. Its totient is φ = 11140654596.
The previous prime is 11140654589. The next prime is 11140654631. The reversal of 11140654597 is 79545604111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7776770596 + 3363884001 = 88186^2 + 57999^2 .
It is a cyclic number.
It is not a de Polignac number, because 11140654597 - 23 = 11140654589 is a prime.
It is a super-2 number, since 2×111406545972 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11140654507) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5570327298 + 5570327299.
It is an arithmetic number, because the mean of its divisors is an integer number (5570327299).
Almost surely, 211140654597 is an apocalyptic number.
It is an amenable number.
11140654597 is a deficient number, since it is larger than the sum of its proper divisors (1).
11140654597 is an equidigital number, since it uses as much as digits as its factorization.
11140654597 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 151200, while the sum is 43.
The spelling of 11140654597 in words is "eleven billion, one hundred forty million, six hundred fifty-four thousand, five hundred ninety-seven".
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