111410444113 has 2 divisors, whose sum is σ = 111410444114. Its totient is φ = 111410444112.

The previous prime is 111410444059. The next prime is 111410444149. The reversal of 111410444113 is 311444014111.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 87294838849 + 24115605264 = 295457^2 + 155292^2 .

It is a cyclic number.

It is not a de Polignac number, because 111410444113 - 2¹³ = 111410435921 is a prime.

It is not a weakly prime, because it can be changed into another prime (111410444183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55705222056 + 55705222057.

It is an arithmetic number, because the mean of its divisors is an integer number (55705222057).

Almost surely, 2^111410444113 is an apocalyptic number.

It is an amenable number.

111410444113 is a deficient number, since it is larger than the sum of its proper divisors (1).

111410444113 is an equidigital number, since it uses as much as digits as its factorization.

111410444113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 111410444113 its reverse (311444014111), we get a palindrome (422854458224).

The spelling of 111410444113 in words is "one hundred eleven billion, four hundred ten million, four hundred forty-four thousand, one hundred thirteen".