Base | Representation |
---|---|
bin | 10100110000000111… |
… | …01101100100001101 |
3 | 1001202102211200220112 |
4 | 22120003231210031 |
5 | 140304101410433 |
6 | 5041303125405 |
7 | 543041213165 |
oct | 123003554415 |
9 | 31672750815 |
10 | 11141044493 |
11 | 47a7913697 |
12 | 21ab143865 |
13 | 108720c227 |
14 | 7799075a5 |
15 | 453150348 |
hex | 2980ed90d |
11141044493 has 2 divisors, whose sum is σ = 11141044494. Its totient is φ = 11141044492.
The previous prime is 11141044483. The next prime is 11141044501. The reversal of 11141044493 is 39444014111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8626322884 + 2514721609 = 92878^2 + 50147^2 .
It is an emirp because it is prime and its reverse (39444014111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11141044493 - 28 = 11141044237 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11141044403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5570522246 + 5570522247.
It is an arithmetic number, because the mean of its divisors is an integer number (5570522247).
Almost surely, 211141044493 is an apocalyptic number.
It is an amenable number.
11141044493 is a deficient number, since it is larger than the sum of its proper divisors (1).
11141044493 is an equidigital number, since it uses as much as digits as its factorization.
11141044493 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 32.
The spelling of 11141044493 in words is "eleven billion, one hundred forty-one million, forty-four thousand, four hundred ninety-three".
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