Base | Representation |
---|---|
bin | 10000001101100110001… |
… | …100010011101011000010 |
3 | 10221111201022110110120122 |
4 | 100031212030103223002 |
5 | 121223144411011002 |
6 | 2211452053540242 |
7 | 143330465343353 |
oct | 20154614235302 |
9 | 3844638413518 |
10 | 1114111032002 |
11 | 39a5456a6211 |
12 | 15bb09644682 |
13 | 810a23c1157 |
14 | 3bccd603d2a |
15 | 1dea97176a2 |
hex | 10366313ac2 |
1114111032002 has 4 divisors (see below), whose sum is σ = 1671166548006. Its totient is φ = 557055516000.
The previous prime is 1114111031977. The next prime is 1114111032043. The reversal of 1114111032002 is 2002301114111.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1064118096721 + 49992935281 = 1031561^2 + 223591^2 .
It is a super-2 number, since 2×11141110320022 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 278527757999 + ... + 278527758002.
Almost surely, 21114111032002 is an apocalyptic number.
1114111032002 is a deficient number, since it is larger than the sum of its proper divisors (557055516004).
1114111032002 is an equidigital number, since it uses as much as digits as its factorization.
1114111032002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 557055516003.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 1114111032002 its reverse (2002301114111), we get a palindrome (3116412146113).
The spelling of 1114111032002 in words is "one trillion, one hundred fourteen billion, one hundred eleven million, thirty-two thousand, two".
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