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1114111032002 = 2557055516001
BaseRepresentation
bin10000001101100110001…
…100010011101011000010
310221111201022110110120122
4100031212030103223002
5121223144411011002
62211452053540242
7143330465343353
oct20154614235302
93844638413518
101114111032002
1139a5456a6211
1215bb09644682
13810a23c1157
143bccd603d2a
151dea97176a2
hex10366313ac2

1114111032002 has 4 divisors (see below), whose sum is σ = 1671166548006. Its totient is φ = 557055516000.

The previous prime is 1114111031977. The next prime is 1114111032043. The reversal of 1114111032002 is 2002301114111.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1064118096721 + 49992935281 = 1031561^2 + 223591^2 .

It is a super-2 number, since 2×11141110320022 (a number of 25 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 278527757999 + ... + 278527758002.

Almost surely, 21114111032002 is an apocalyptic number.

1114111032002 is a deficient number, since it is larger than the sum of its proper divisors (557055516004).

1114111032002 is an equidigital number, since it uses as much as digits as its factorization.

1114111032002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 557055516003.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 1114111032002 its reverse (2002301114111), we get a palindrome (3116412146113).

The spelling of 1114111032002 in words is "one trillion, one hundred fourteen billion, one hundred eleven million, thirty-two thousand, two".

Divisors: 1 2 557055516001 1114111032002