Base | Representation |
---|---|
bin | 110011111000010011… |
… | …1101101011110010101 |
3 | 101122120102200111202021 |
4 | 1213300213231132111 |
5 | 3311132221432432 |
6 | 123103115013141 |
7 | 11022604633636 |
oct | 1476047553625 |
9 | 348512614667 |
10 | 111411124117 |
11 | 43281747597 |
12 | 1971343a1b1 |
13 | a676971aa7 |
14 | 556c78d88d |
15 | 2d70e38697 |
hex | 19f09ed795 |
111411124117 has 2 divisors, whose sum is σ = 111411124118. Its totient is φ = 111411124116.
The previous prime is 111411124073. The next prime is 111411124151. The reversal of 111411124117 is 711421114111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 70326266481 + 41084857636 = 265191^2 + 202694^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-111411124117 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 111411124091 and 111411124100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111411124157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55705562058 + 55705562059.
It is an arithmetic number, because the mean of its divisors is an integer number (55705562059).
Almost surely, 2111411124117 is an apocalyptic number.
It is an amenable number.
111411124117 is a deficient number, since it is larger than the sum of its proper divisors (1).
111411124117 is an equidigital number, since it uses as much as digits as its factorization.
111411124117 is an evil number, because the sum of its binary digits is even.
The product of its digits is 224, while the sum is 25.
Adding to 111411124117 its reverse (711421114111), we get a palindrome (822832238228).
The spelling of 111411124117 in words is "one hundred eleven billion, four hundred eleven million, one hundred twenty-four thousand, one hundred seventeen".
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