Base | Representation |
---|---|
bin | 11001010101001111110111… |
… | …101011110000100001101001 |
3 | 112121110211001220022112112002 |
4 | 121111033313223300201221 |
5 | 104100330331401243444 |
6 | 1032541352240500345 |
7 | 32316126113651051 |
oct | 3125176753604151 |
9 | 477424056275462 |
10 | 111411312134249 |
11 | 325542aa238366 |
12 | 105b431301a6b5 |
13 | 4a2207068b89a |
14 | 1d7249ca6c561 |
15 | cd30e5a1ad4e |
hex | 6553f7af0869 |
111411312134249 has 2 divisors, whose sum is σ = 111411312134250. Its totient is φ = 111411312134248.
The previous prime is 111411312134207. The next prime is 111411312134273. The reversal of 111411312134249 is 942431213114111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 93347384106025 + 18063928028224 = 9661645^2 + 4250168^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-111411312134249 is a prime.
It is a super-3 number, since 3×1114113121342493 (a number of 43 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (111411312134279) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55705656067124 + 55705656067125.
It is an arithmetic number, because the mean of its divisors is an integer number (55705656067125).
Almost surely, 2111411312134249 is an apocalyptic number.
It is an amenable number.
111411312134249 is a deficient number, since it is larger than the sum of its proper divisors (1).
111411312134249 is an equidigital number, since it uses as much as digits as its factorization.
111411312134249 is an evil number, because the sum of its binary digits is even.
The product of its digits is 20736, while the sum is 38.
The spelling of 111411312134249 in words is "one hundred eleven trillion, four hundred eleven billion, three hundred twelve million, one hundred thirty-four thousand, two hundred forty-nine".
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