Base | Representation |
---|---|
bin | 11001010101001111110111… |
… | …101011110000100000111111 |
3 | 112121110211001220022112110112 |
4 | 121111033313223300200333 |
5 | 104100330331401243312 |
6 | 1032541352240500235 |
7 | 32316126113650661 |
oct | 3125176753604077 |
9 | 477424056275415 |
10 | 111411312134207 |
11 | 325542aa238328 |
12 | 105b431301a67b |
13 | 4a2207068b867 |
14 | 1d7249ca6c531 |
15 | cd30e5a1ad22 |
hex | 6553f7af083f |
111411312134207 has 2 divisors, whose sum is σ = 111411312134208. Its totient is φ = 111411312134206.
The previous prime is 111411312134197. The next prime is 111411312134249. The reversal of 111411312134207 is 702431213114111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 111411312134207 - 232 = 111407017166911 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111411312134407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55705656067103 + 55705656067104.
It is an arithmetic number, because the mean of its divisors is an integer number (55705656067104).
Almost surely, 2111411312134207 is an apocalyptic number.
111411312134207 is a deficient number, since it is larger than the sum of its proper divisors (1).
111411312134207 is an equidigital number, since it uses as much as digits as its factorization.
111411312134207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 32.
Adding to 111411312134207 its reverse (702431213114111), we get a palindrome (813842525248318).
The spelling of 111411312134207 in words is "one hundred eleven trillion, four hundred eleven billion, three hundred twelve million, one hundred thirty-four thousand, two hundred seven".
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