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11141202002 = 27795800143
BaseRepresentation
bin10100110000001000…
…10100000001010010
31001202110010200222012
422120010110001102
5140304121431002
65041310342522
7543042440330
oct123004240122
931673120865
1011141202002
1147a7a10a67
1221ab1baa42
131087265b28
14779948b50
15453181d52
hex298114052

11141202002 has 8 divisors (see below), whose sum is σ = 19099203456. Its totient is φ = 4774800852.

The previous prime is 11141201993. The next prime is 11141202013. The reversal of 11141202002 is 20020214111.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-3 number, since 3×111412020023 (a number of 31 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (14), and also a Moran number because the ratio is a prime number: 795800143 = 11141202002 / (1 + 1 + 1 + 4 + 1 + 2 + 0 + 2 + 0 + 0 + 2).

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 397900058 + ... + 397900085.

It is an arithmetic number, because the mean of its divisors is an integer number (2387400432).

Almost surely, 211141202002 is an apocalyptic number.

11141202002 is a deficient number, since it is larger than the sum of its proper divisors (7958001454).

11141202002 is an equidigital number, since it uses as much as digits as its factorization.

11141202002 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 795800152.

The product of its (nonzero) digits is 32, while the sum is 14.

Adding to 11141202002 its reverse (20020214111), we get a palindrome (31161416113).

The spelling of 11141202002 in words is "eleven billion, one hundred forty-one million, two hundred two thousand, two".

Divisors: 1 2 7 14 795800143 1591600286 5570601001 11141202002