1114120441133 has 4 divisors (see below), whose sum is σ = 1273280504160. Its totient is φ = 954960378108.

The previous prime is 1114120441127. The next prime is 1114120441151. The reversal of 1114120441133 is 3311440214111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1114120441133 - 2¹⁶ = 1114120375597 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1114120441193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 79580031503 + ... + 79580031516.

It is an arithmetic number, because the mean of its divisors is an integer number (318320126040).

Almost surely, 2^{1114120441133} is an apocalyptic number.

It is an amenable number.

1114120441133 is a deficient number, since it is larger than the sum of its proper divisors (159160063027).

1114120441133 is an equidigital number, since it uses as much as digits as its factorization.

1114120441133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 159160063026.

The product of its (nonzero) digits is 1152, while the sum is 26.

Adding to 1114120441133 its reverse (3311440214111), we get a palindrome (4425560655244).

The spelling of 1114120441133 in words is "one trillion, one hundred fourteen billion, one hundred twenty million, four hundred forty-one thousand, one hundred thirty-three".