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1114131431423 = 2203505733741
BaseRepresentation
bin10000001101100111011…
…010000111111111111111
310221111202201211212022202
4100031213122013333333
5121223220121301143
62211454103102115
7143331133625033
oct20154732077777
93844681755282
101114131431423
1139a55616963a
1215bb1444193b
13810a66b430a
143bcd21d41c3
151deab3e6ab8
hex10367687fff

1114131431423 has 4 divisors (see below), whose sum is σ = 1114637167368. Its totient is φ = 1113625695480.

The previous prime is 1114131431417. The next prime is 1114131431443. The reversal of 1114131431423 is 3241341314111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1114131431423 - 28 = 1114131431167 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1114131431443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 252864668 + ... + 252869073.

It is an arithmetic number, because the mean of its divisors is an integer number (278659291842).

Almost surely, 21114131431423 is an apocalyptic number.

1114131431423 is a deficient number, since it is larger than the sum of its proper divisors (505735945).

1114131431423 is an equidigital number, since it uses as much as digits as its factorization.

1114131431423 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 505735944.

The product of its digits is 3456, while the sum is 29.

Adding to 1114131431423 its reverse (3241341314111), we get a palindrome (4355472745534).

The spelling of 1114131431423 in words is "one trillion, one hundred fourteen billion, one hundred thirty-one million, four hundred thirty-one thousand, four hundred twenty-three".

Divisors: 1 2203 505733741 1114131431423