1114133347001 has 2 divisors, whose sum is σ = 1114133347002. Its totient is φ = 1114133347000.

The previous prime is 1114133346973. The next prime is 1114133347003. The reversal of 1114133347001 is 1007433314111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1110030816400 + 4102530601 = 1053580^2 + 64051^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1114133347001 is a prime.

It is a super-2 number, since 2×1114133347001² (a number of 25 digits) contains 22 as substring.

Together with 1114133347003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1114133347003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557066673500 + 557066673501.

It is an arithmetic number, because the mean of its divisors is an integer number (557066673501).

Almost surely, 2^{1114133347001} is an apocalyptic number.

It is an amenable number.

1114133347001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1114133347001 is an equidigital number, since it uses as much as digits as its factorization.

1114133347001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3024, while the sum is 29.

The spelling of 1114133347001 in words is "one trillion, one hundred fourteen billion, one hundred thirty-three million, three hundred forty-seven thousand, one".