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111414155051 is a prime number
BaseRepresentation
bin110011111000011001…
…1010001011100101011
3101122120122101111102002
41213300303101130223
53311134010430201
6123103304001215
711022642456323
oct1476063213453
9348518344362
10111414155051
11432834277a1
121971446020b
13a677493544
14556cd3c283
152d7133676b
hex19f0cd172b

111414155051 has 2 divisors, whose sum is σ = 111414155052. Its totient is φ = 111414155050.

The previous prime is 111414155029. The next prime is 111414155053. The reversal of 111414155051 is 150551414111.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 111414155051 - 222 = 111409960747 is a prime.

It is a super-2 number, since 2×1114141550512 (a number of 23 digits) contains 22 as substring.

Together with 111414155053, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (111414155053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55707077525 + 55707077526.

It is an arithmetic number, because the mean of its divisors is an integer number (55707077526).

Almost surely, 2111414155051 is an apocalyptic number.

111414155051 is a deficient number, since it is larger than the sum of its proper divisors (1).

111414155051 is an equidigital number, since it uses as much as digits as its factorization.

111414155051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2000, while the sum is 29.

Adding to 111414155051 its reverse (150551414111), we get a palindrome (261965569162).

The spelling of 111414155051 in words is "one hundred eleven billion, four hundred fourteen million, one hundred fifty-five thousand, fifty-one".