Base | Representation |
---|---|
bin | 10100110000001010… |
… | …01110001001010111 |
3 | 1001202110120210120011 |
4 | 22120011032021113 |
5 | 140304202040322 |
6 | 5041315421051 |
7 | 543044451421 |
oct | 123005161127 |
9 | 31673523504 |
10 | 11141440087 |
11 | 47a8063928 |
12 | 21ab2b4787 |
13 | 108731a2cb |
14 | 7799ab811 |
15 | 4531cc677 |
hex | 29814e257 |
11141440087 has 2 divisors, whose sum is σ = 11141440088. Its totient is φ = 11141440086.
The previous prime is 11141440067. The next prime is 11141440187. The reversal of 11141440087 is 78004414111.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11141440087 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11141440067) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5570720043 + 5570720044.
It is an arithmetic number, because the mean of its divisors is an integer number (5570720044).
Almost surely, 211141440087 is an apocalyptic number.
11141440087 is a deficient number, since it is larger than the sum of its proper divisors (1).
11141440087 is an equidigital number, since it uses as much as digits as its factorization.
11141440087 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3584, while the sum is 31.
Adding to 11141440087 its reverse (78004414111), we get a palindrome (89145854198).
The spelling of 11141440087 in words is "eleven billion, one hundred forty-one million, four hundred forty thousand, eighty-seven".
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