11141443433 has 2 divisors, whose sum is σ = 11141443434. Its totient is φ = 11141443432.

The previous prime is 11141443429. The next prime is 11141443463. The reversal of 11141443433 is 33434414111.

11141443433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9887716969 + 1253726464 = 99437^2 + 35408^2 .

It is a cyclic number.

It is not a de Polignac number, because 11141443433 - 2² = 11141443429 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11141443396 and 11141443405.

It is not a weakly prime, because it can be changed into another prime (11141443463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5570721716 + 5570721717.

It is an arithmetic number, because the mean of its divisors is an integer number (5570721717).

Almost surely, 2^11141443433 is an apocalyptic number.

It is an amenable number.

11141443433 is a deficient number, since it is larger than the sum of its proper divisors (1).

11141443433 is an equidigital number, since it uses as much as digits as its factorization.

11141443433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6912, while the sum is 29.

Adding to 11141443433 its reverse (33434414111), we get a palindrome (44575857544).

The spelling of 11141443433 in words is "eleven billion, one hundred forty-one million, four hundred forty-three thousand, four hundred thirty-three".