Base | Representation |
---|---|
bin | 10000001101101001001… |
… | …011110110001000001011 |
3 | 10221111211210221102121201 |
4 | 100031221023312020023 |
5 | 121223300234231020 |
6 | 2211501050045031 |
7 | 143331645206140 |
oct | 20155113661013 |
9 | 3844753842551 |
10 | 1114161242635 |
11 | 39a570a80201 |
12 | 15bb22419777 |
13 | 810ac92139c |
14 | 3bcd61543c7 |
15 | 1deadd34a0a |
hex | 103692f620b |
1114161242635 has 8 divisors (see below), whose sum is σ = 1527992561376. Its totient is φ = 763996280640.
The previous prime is 1114161242617. The next prime is 1114161242723. The reversal of 1114161242635 is 5362421614111.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1114161242635 - 215 = 1114161209867 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1114161242594 and 1114161242603.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15916589146 + ... + 15916589215.
It is an arithmetic number, because the mean of its divisors is an integer number (190999070172).
Almost surely, 21114161242635 is an apocalyptic number.
1114161242635 is a deficient number, since it is larger than the sum of its proper divisors (413831318741).
1114161242635 is an equidigital number, since it uses as much as digits as its factorization.
1114161242635 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31833178373.
The product of its digits is 34560, while the sum is 37.
Adding to 1114161242635 its reverse (5362421614111), we get a palindrome (6476582856746).
The spelling of 1114161242635 in words is "one trillion, one hundred fourteen billion, one hundred sixty-one million, two hundred forty-two thousand, six hundred thirty-five".
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