11142104131 has 2 divisors, whose sum is σ = 11142104132. Its totient is φ = 11142104130.

The previous prime is 11142104069. The next prime is 11142104137. The reversal of 11142104131 is 13140124111.

It is a strong prime.

It is an emirp because it is prime and its reverse (13140124111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11142104131 - 2¹⁵ = 11142071363 is a prime.

It is a super-2 number, since 2×11142104131² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11142104099 and 11142104108.

It is not a weakly prime, because it can be changed into another prime (11142104137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5571052065 + 5571052066.

It is an arithmetic number, because the mean of its divisors is an integer number (5571052066).

Almost surely, 2^11142104131 is an apocalyptic number.

11142104131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11142104131 is an equidigital number, since it uses as much as digits as its factorization.

11142104131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 11142104131 its reverse (13140124111), we get a palindrome (24282228242).

The spelling of 11142104131 in words is "eleven billion, one hundred forty-two million, one hundred four thousand, one hundred thirty-one".