Base | Representation |
---|---|
bin | 110011111000100111… |
… | …0110001101101111001 |
3 | 101122121010221210202102 |
4 | 1213301032301231321 |
5 | 3311142332140423 |
6 | 123104122313145 |
7 | 11023060656032 |
oct | 1476116615571 |
9 | 348533853672 |
10 | 111421365113 |
11 | 43287501823 |
12 | 197169587b5 |
13 | a678b19256 |
14 | 556dc97a89 |
15 | 2d71cacc28 |
hex | 19f13b1b79 |
111421365113 has 2 divisors, whose sum is σ = 111421365114. Its totient is φ = 111421365112.
The previous prime is 111421365103. The next prime is 111421365127. The reversal of 111421365113 is 311563124111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 63167774224 + 48253590889 = 251332^2 + 219667^2 .
It is an emirp because it is prime and its reverse (311563124111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 111421365113 - 214 = 111421348729 is a prime.
It is not a weakly prime, because it can be changed into another prime (111421365103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55710682556 + 55710682557.
It is an arithmetic number, because the mean of its divisors is an integer number (55710682557).
Almost surely, 2111421365113 is an apocalyptic number.
It is an amenable number.
111421365113 is a deficient number, since it is larger than the sum of its proper divisors (1).
111421365113 is an equidigital number, since it uses as much as digits as its factorization.
111421365113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2160, while the sum is 29.
Adding to 111421365113 its reverse (311563124111), we get a palindrome (422984489224).
The spelling of 111421365113 in words is "one hundred eleven billion, four hundred twenty-one million, three hundred sixty-five thousand, one hundred thirteen".
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