Base | Representation |
---|---|
bin | 110011111000101011… |
… | …0100100111110100011 |
3 | 101122121021210200221001 |
4 | 1213301112210332203 |
5 | 3311143343110313 |
6 | 123104234212431 |
7 | 11023114234036 |
oct | 1476126447643 |
9 | 348537720831 |
10 | 111423410083 |
11 | 43288679187 |
12 | 19717584117 |
13 | a679383cab |
14 | 557026b01d |
15 | 2d72063add |
hex | 19f15a4fa3 |
111423410083 has 2 divisors, whose sum is σ = 111423410084. Its totient is φ = 111423410082.
The previous prime is 111423410011. The next prime is 111423410107. The reversal of 111423410083 is 380014324111.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-111423410083 is a prime.
It is not a weakly prime, because it can be changed into another prime (111423420083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55711705041 + 55711705042.
It is an arithmetic number, because the mean of its divisors is an integer number (55711705042).
Almost surely, 2111423410083 is an apocalyptic number.
111423410083 is a deficient number, since it is larger than the sum of its proper divisors (1).
111423410083 is an equidigital number, since it uses as much as digits as its factorization.
111423410083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 28.
Adding to 111423410083 its reverse (380014324111), we get a palindrome (491437734194).
The spelling of 111423410083 in words is "one hundred eleven billion, four hundred twenty-three million, four hundred ten thousand, eighty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.084 sec. • engine limits •