1114244041331 has 4 divisors (see below), whose sum is σ = 1114627077600. Its totient is φ = 1113861005064.

The previous prime is 1114244041283. The next prime is 1114244041399. The reversal of 1114244041331 is 1331404424111.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1114244041331 is a prime.

It is a super-2 number, since 2×1114244041331² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1114244041294 and 1114244041303.

It is not an unprimeable number, because it can be changed into a prime (1114244041531) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 191513771 + ... + 191519588.

It is an arithmetic number, because the mean of its divisors is an integer number (278656769400).

Almost surely, 2^{1114244041331} is an apocalyptic number.

1114244041331 is a deficient number, since it is larger than the sum of its proper divisors (383036269).

1114244041331 is an equidigital number, since it uses as much as digits as its factorization.

1114244041331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 383036268.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 1114244041331 its reverse (1331404424111), we get a palindrome (2445648465442).

The spelling of 1114244041331 in words is "one trillion, one hundred fourteen billion, two hundred forty-four million, forty-one thousand, three hundred thirty-one".