Base | Representation |
---|---|
bin | 10100110000011000… |
… | …11011101001100011 |
3 | 1001202121010211120212 |
4 | 22120030123221203 |
5 | 140310143033103 |
6 | 5041424124335 |
7 | 543066513512 |
oct | 123014335143 |
9 | 31677124525 |
10 | 11143330403 |
11 | 47a9135077 |
12 | 21aba666ab |
13 | 108782c83a |
14 | 779d40679 |
15 | 4534527d8 |
hex | 29831ba63 |
11143330403 has 2 divisors, whose sum is σ = 11143330404. Its totient is φ = 11143330402.
The previous prime is 11143330399. The next prime is 11143330409. The reversal of 11143330403 is 30403334111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11143330403 - 22 = 11143330399 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (11143330409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5571665201 + 5571665202.
It is an arithmetic number, because the mean of its divisors is an integer number (5571665202).
Almost surely, 211143330403 is an apocalyptic number.
11143330403 is a deficient number, since it is larger than the sum of its proper divisors (1).
11143330403 is an equidigital number, since it uses as much as digits as its factorization.
11143330403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 11143330403 its reverse (30403334111), we get a palindrome (41546664514).
The spelling of 11143330403 in words is "eleven billion, one hundred forty-three million, three hundred thirty thousand, four hundred three".
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