Base | Representation |
---|---|
bin | 110011111000111110… |
… | …0101100000000010111 |
3 | 101122121222121020222200 |
4 | 1213301330230000113 |
5 | 3311203422302333 |
6 | 123105232255543 |
7 | 11023265163126 |
oct | 1476174540027 |
9 | 348558536880 |
10 | 111433400343 |
11 | 43293281aa1 |
12 | 1971a9a15b3 |
13 | a67b4712a5 |
14 | 557170babd |
15 | 2d72d88c13 |
hex | 19f1f2c017 |
111433400343 has 12 divisors (see below), whose sum is σ = 161632829280. Its totient is φ = 73978099776.
The previous prime is 111433400339. The next prime is 111433400347. The reversal of 111433400343 is 343004334111.
It is an interprime number because it is at equal distance from previous prime (111433400339) and next prime (111433400347).
It is not a de Polignac number, because 111433400343 - 22 = 111433400339 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (111433400347) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 25900546 + ... + 25904847.
It is an arithmetic number, because the mean of its divisors is an integer number (13469402440).
Almost surely, 2111433400343 is an apocalyptic number.
111433400343 is a deficient number, since it is larger than the sum of its proper divisors (50199428937).
111433400343 is a wasteful number, since it uses less digits than its factorization.
111433400343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 51805638 (or 51805635 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 27.
Adding to 111433400343 its reverse (343004334111), we get a palindrome (454437734454).
The spelling of 111433400343 in words is "one hundred eleven billion, four hundred thirty-three million, four hundred thousand, three hundred forty-three".
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