Base | Representation |
---|---|
bin | 10000001101110011110… |
… | …101110111101101010001 |
3 | 10221112022021100211120121 |
4 | 100031303311313231101 |
5 | 121224132022000223 |
6 | 2211530514110241 |
7 | 143336245661005 |
oct | 20156365675521 |
9 | 3845267324517 |
10 | 1114340031313 |
11 | 39a652995843 |
12 | 15bb7227b381 |
13 | 8110a98cac2 |
14 | 3bd11bb4705 |
15 | 1debe89e15d |
hex | 10373d77b51 |
1114340031313 has 8 divisors (see below), whose sum is σ = 1150403143680. Its totient is φ = 1078284210240.
The previous prime is 1114340031283. The next prime is 1114340031359. The reversal of 1114340031313 is 3131300434111.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1114340031313 - 29 = 1114340030801 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1114340031713) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1511368 + ... + 2124361.
It is an arithmetic number, because the mean of its divisors is an integer number (143800392960).
Almost surely, 21114340031313 is an apocalyptic number.
It is an amenable number.
1114340031313 is a deficient number, since it is larger than the sum of its proper divisors (36063112367).
1114340031313 is an equidigital number, since it uses as much as digits as its factorization.
1114340031313 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3645647.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 1114340031313 its reverse (3131300434111), we get a palindrome (4245640465424).
The spelling of 1114340031313 in words is "one trillion, one hundred fourteen billion, three hundred forty million, thirty-one thousand, three hundred thirteen".
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